81^x^2-1=27^-(7-5x)

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Solution for 81^x^2-1=27^-(7-5x) equation: 



81^x^2-1=27^-(7-5x)

We move all terms to the left:

81^x^2-1-(27^-(7-5x))=0

We add all the numbers together, and all the variables

81^x^2-(27^-(-5x+7))-1=0



We calculate terms in parentheses: -(27^-(-5x+7)), so:

27^-(-5x+7)

determiningTheFunctionDomain
-(-5x+7)+27^

We add all the numbers together, and all the variables

-(-5x+7)

We get rid of parentheses

5x-7

Back to the equation:

-(5x-7)



We get rid of parentheses

81^x^2-5x+7-1=0

We add all the numbers together, and all the variables

-5x+81^x^2+6=0

We move all terms containing x to the left, all other terms to the right

-5x+81^x^2=-6

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